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5x^2+44x-60=0
a = 5; b = 44; c = -60;
Δ = b2-4ac
Δ = 442-4·5·(-60)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-56}{2*5}=\frac{-100}{10} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+56}{2*5}=\frac{12}{10} =1+1/5 $
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